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批踢踢實業坊 Examination 板
 
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[問題] 電力系統
Oct 18th 2013, 14:53, by kkcaros

作者kkcaros ()

看板Examination

標題[問題] 電力系統

時間Fri Oct 18 14:53:15 2013

99高考 題目:http://ppt.cc/ue13 已知 x0,x1,x2 求xn 我的想法 先畫出兩種故障的等效電路 1.三相接地故障 :只有正序電路 所以If = Ia1 = Ea/x1 = 1/j0.25 = -j4 2.雙相接地故障(假設是b.c相接地) 為一個正序電路並聯(負序電抗)並聯(零序電抗+3*接地電抗(Xn)) 所以可以求得Zin = x1 + x2//(x0+3xn) 並求得Ia1 = Ea/Zin 並透過分流可求得 Ia2 = -Ia1*(x0+3xn)/(x2+x0+3xn) Ia0 = -Ia1*(x2)/(x2+x0+3xn) 又因為故障電流 If = Ib(orIc也可) Ib = Ia0+a*a*Ia1+a*Ia2 最後再利用 Ib = -j4 來解方程式 寫到這邊我就掛了 不知道怎解這個變數 還是我想法有錯 麻煩各位熱心的板友能幫忙解惑 非常感謝^^ Ps 我也看了李進雲老師 的解答 但是看不太懂她寫的= = -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.109.23.73

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